A) \[-0.177V~\]
B) \[-0.236V\]
C) \[+\text{ }0.177V\]
D) \[+\text{ }0.236V\]
Correct Answer: B
Solution :
\[E={{E}^{o}}-\frac{0.059}{n}\log \frac{1}{[{{M}^{n+}}]}\] \[=0-\frac{0.059}{1}\log \frac{[1]}{[{{10}^{-4}}]}\] \[=-0.236V\]You need to login to perform this action.
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