A) 100\[=\frac{5\times {{10}^{-2}}\times 0.314\times {{10}^{-4}}}{{{10}^{-6}}\times 2\times 3.14\times 50}\], 100\[\lambda \]
B) 200\[\overset{0}{\mathop{A}}\,\], 100\[I\]
C) 200\[I\], 200\[(\sqrt{3}+1)/1\]
D) 100\[\sqrt{3}/1\], 200\[(\sqrt{3}+1)/(\sqrt{3}-1)\]
Correct Answer: C
Solution :
The equivalent capacitance, for capacitors in series is \[6\times {{10}^{4}}\] \[6\times {{10}^{-3}}\] \[6\times {{10}^{-6}}\] Also, \[\frac{Q}{q}\] This charge on the two capacitors in series is same. Hence, \[A=4i+4j-4k\]You need to login to perform this action.
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