A) 0.2 J
B) 2 J
C) 4.18 J
D) \[2\times {{10}^{2}}J\]
Correct Answer: A
Solution :
Magnetic moment \[\cos \phi =\frac{R}{\sqrt{{{R}^{2}}+{{\omega }^{2}}{{L}^{2}}}}\] \[\approx \frac{R}{\omega L}\] Work done in moving the magnet in uniform magnetic field. \[R<<\omega L\] \[R<<\omega L\] \[\cos \phi \]
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