A) \[{{e}^{-1}}\]
B) \[(1-{{e}^{-1}})\]
C) \[(1-e)\]
D) e
Correct Answer: B
Solution :
Given, \[\delta =(n-1)A\] and \[({{n}_{1}}-1){{A}_{1}}=({{n}_{2}}-1){{A}_{2}}\] s. Current in R-L circuit \[{{A}_{2}}\frac{({{n}_{1}}-1){{A}_{1}}}{({{n}_{2}}-1)}=\frac{(1.54-1)\times 4}{(1.72-1)}={{3}^{o}}\] \[{{P}_{2}}\] \[={{3}^{o}}\] \[E=\frac{hc}{\lambda }\]
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