A) 0.5 V with plane of coil normal to die magnetic meridian
B) 0.5 V with plane of coil in the magnetic meridian
C) 0.25 V with plane of coil normal to the magnetic meridian
D) 0.25 V with plane of coil in the magnetic meridian
Correct Answer: C
Solution :
Given, \[=\frac{5}{5}(1-{{e}^{-5\times 2/10}})\], \[I=(1-{{e}^{-1}})\] \[v=u-gt\] and \[0=u-9.8\times 5\] gauss For circular coil, \[=49m/s\] or \[h=ut-\frac{1}{2}g{{t}^{2}}\] \[=0-\frac{1}{2}\times 98\times {{(5)}^{2}}\] \[=\frac{245}{2}m\] \[{{v}^{2}}={{u}^{2}}-2gh\] \[0={{u}^{2}}-2gh\] Magnetic field produced due to the coil is normal to the plane of coil so the plane of the coil should be normal to the magnetic meridian. Hence choice is correct.
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