A) 1\[i=\frac{E}{R+r}\]
B) 1.3872\[=\frac{2.5}{1+1+0.5}=1amp\]
C) 0.3541\[V=E-ir\]
D) 0.5\[=2.5-1\times 0.5=2V\]
Correct Answer: B
Solution :
Wavelength \[={{F}_{s}}\,\,d\cos \theta \] Energy \[=\mu Rd\cos \theta \] \[({{F}_{s}}=\mu R)\] \[W=\mu mgd\cos \theta \] \[(R=mg)\] \[-ve\] \[+ve\]You need to login to perform this action.
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