A) 2
B) 1/2
C) 4
D) 1/4
Correct Answer: A
Solution :
Let distance between two charges is x. The force between them. \[i=\frac{4\pi }{{{\mu }_{0}}}\frac{rH}{2\pi n}\] x is constant, so for maximum force \[=\frac{5\times {{10}^{-2}}\times 0.314\times {{10}^{-4}}}{{{10}^{-6}}\times 2\times 3.14\times 50}\]should be maximum. \[=5\times {{10}^{-2}}A\] \[=5\times {{10}^{-2}}A\] \[\lambda \] \[\overset{0}{\mathop{A}}\,\]You need to login to perform this action.
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