A) 4/3
B) \[={{h}_{1}}+{{h}_{2}}=\frac{245}{2}+\frac{245}{2}=245m\]
C) \[Work=force\times displacement\]
D) \[={{F}_{s}}.d\]
Correct Answer: C
Solution :
For tangent galvanometer \[=15mm=1.5cm\] \[C=\frac{{{\varepsilon }_{0}}A}{d}\] \[=\frac{8.854\times {{10}^{-12}}\times 5\times {{10}^{-4}}}{0.885\times {{10}^{-2}}}=0.5pF\] \[=8C=8\times 0.5=4pF\]You need to login to perform this action.
You will be redirected in
3 sec