A) 2
B) 3
C) 4
D) 1
Correct Answer: C
Solution :
For Lyman series, \[\frac{1}{\lambda }=R\left[ \frac{1}{{{1}^{2}}}-\frac{1}{n_{2}^{2}} \right]\] \[\frac{15R}{16}=R\left[ \frac{1}{{{1}^{2}}}-\frac{1}{n_{2}^{2}} \right]\] \[\frac{15R}{16R}=R\left[ \frac{n_{2}^{2}-1}{n_{2}^{2}} \right]\] \[\frac{15}{16}=\frac{n_{2}^{2}-1}{n_{2}^{2}}\] \[15n_{2}^{2}=16n_{2}^{2}-16\] \[n_{2}^{2}=16\] \[{{n}_{2}}=4\]
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