AIIMS AIIMS Solved Paper-2011

  • question_answer
    138 g of ethyl alcohol is mixed with 72 g of water. The ratio of mole fraction of alcohol to water is

    A)  \[3:4\]                 

    B)         \[1:2\]                 

    C)  \[1:4\]                 

    D)         \[1:1\]

    Correct Answer: A

    Solution :

    Number of moles of ethyl alcohol \[=\frac{138}{46}=3\] Number of moles of water \[=\frac{72}{18}=4\] \[{{X}_{{{C}_{2}}{{H}_{5}}OH}}=\frac{3}{3+4}\] \[=\frac{3}{7}\] \[{{X}_{{{H}_{2}}O}}=\frac{4}{3+4}\] \[=\frac{4}{7}\] \[\frac{{{X}_{{{C}_{2}}{{H}_{5}}OH}}}{{{X}_{{{H}_{2}}O}}}=\frac{3/7}{4/7}\] \[=\frac{3}{4}\]


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