AIIMS AIIMS Solved Paper-2011

  • question_answer
    200 MeV of energy may be obtained per fission of \[{{U}^{235}}\]. A reactor is generating 100 kW of power. The rate of nuclear fission in the reaction is

    A)  1000                                     

    B)  \[2\times {{10}^{8}}\]

    C)  \[3.125\,\times {{10}^{16}}\]                    

    D)         931

    Correct Answer: C

    Solution :

    Energy \[\overset{0}{\mathop{A}}\,\] \[\overset{0}{\mathop{A}}\,\] \[x={{x}_{0}}\sin 2\pi \left( nt-\frac{x}{\lambda } \right)\] Power \[\lambda =\frac{\pi {{x}_{0}}}{4}\] Rate of disintegration \[\lambda =2\pi {{x}_{0}}\] \[\lambda =\frac{\pi {{x}_{0}}}{2}\] \[\lambda =4\pi {{x}_{0}}\]per second


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