AIIMS AIIMS Solved Paper-2011

  • question_answer
    As shown in the figure a magnet is moved with a fast speed towards a coil at rest. Due to this induced emf, induced current and induced charge in the coil is E, \[0={{u}^{2}}-2gh\] and Q respectively. If the speed of the magnet is doubled, the incorrect statement is                       

    A)  E increases        

    B)  \[h=\frac{{{u}^{2}}}{2g}=\frac{49\times 49}{2\times 9.8}=\frac{245}{2}m\] increases     

    C)         Q remains same

    D)        Q decreases

    Correct Answer: D

    Solution :

    Induced emf \[{{C}_{p}}\] or    \[{{C}_{v}}\] and         \[{{C}_{p}}{{C}_{v}}=R\] \[\frac{\Delta p}{\Delta V/V},\]           \[x=\frac{3D\lambda }{d}\] Induced charge \[=\frac{3\times 2\times 5000\times {{10}^{-10}}}{0.2\times {{10}^{-3}}}\] \[=\frac{6\times 5\times {{10}^{-7}}}{2\times {{10}^{-4}}}\] If speed is doubled, then dt decrease, hence, E, I increases, but q will not increase.


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