A) pyridinium chloro-chromate
B) chromic anhydride in glacial acetic acid
C) acidic dichromate
D) acidic permanganate
Correct Answer: B
Solution :
\[C{{H}_{3}}-\overset{{{2}^{o}}}{\mathop{\underset{\underset{OH}{\mathop{|}}\,}{\mathop{C}}\,}}\,H-CH=CH-C{{H}_{3}}\xrightarrow[{}]{}\] \[C{{H}_{3}}-\underset{O}{\mathop{\underset{||}{\mathop{C}}\,}}\,-CH=CH-C{{H}_{3}}\] Only suitable reagent is chromic anhydride in glacial acetic acid. Other will also effect \[(C=C)\]bond.
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