A) 1.5 m
B) 3 m
C) 6m
D) 7.5 m
Correct Answer: B
Solution :
On moon \[{{g}_{m}}=\frac{4}{3}\pi g\left( \frac{R}{4} \right)\left( \frac{2\rho }{3} \right)\] \[=\frac{1}{6}\left( \frac{4}{3}\pi GR\rho \right)=\frac{1}{6}g\] Work done in jumping \[=m\times {{g}_{m}}\times 0.5=m\times \left( \frac{g}{6} \right)m\] \[{{h}_{1}}=0.5\times 6=3.0m\]You need to login to perform this action.
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