A) \[\sqrt{\frac{2g}{L}}\]
B) \[\sqrt{\frac{3g}{L}}\]
C) \[\sqrt{\frac{g}{2L}}\]
D) \[\sqrt{\frac{g}{L}}\]
Correct Answer: B
Solution :
The rod in potential energy = gain in kinetic energy \[mg\frac{L}{2}=\frac{1}{2}\left( \frac{m{{L}^{2}}}{3} \right){{\omega }^{2}}\] \[\omega =\sqrt{\frac{3g}{L}}\]You need to login to perform this action.
You will be redirected in
3 sec