A) 25J
B) 29J
C) 21J
D) 18J
Correct Answer: C
Solution :
To determine the overall work done, we calculate the small work done for the displacement\[dx\]as \[{{O}_{2}}\] \[{{O}_{1}}\] \[{{O}_{2}}\] Now, the total work done for the displacemer from x = 0 to x = 2 unit \[\left( \text{given},\text{hc=124}0\text{ eV}-\text{nm},\text{e}=\text{1}.\text{6}\times \text{1}{{0}^{-\text{19}}}\text{ C} \right)\] \[5\mu A\]You need to login to perform this action.
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