A) I and II
B) II and III
C) I, II and III
D) I and III
Correct Answer: A
Solution :
Bond order of \[N_{2}^{+}\] is 2.5 and that of \[{{N}_{2}}\]is 3. Thus, former bond is weaker and longer. Bond order of NO and \[N{{O}^{+}}\] are 2.5 and 3 respectively. Thus, bond length in \[N{{O}^{+}}\] is less than that of NO. Bond order of\[O_{2}^{2-}\]and \[O_{2}^{{}}\] are 1 and 2 respectively. Therefore, \[O_{2}^{{}}\] bond must be shorter.You need to login to perform this action.
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