A) \[T{{i}^{4+}}\]
B) \[C{{u}^{+}}\]
C) \[Z{{n}^{2+}}\]
D) \[C{{r}^{3+}}\]
Correct Answer: D
Solution :
\[C{{r}^{3+}}=\text{ }1{{s}^{2}},\text{ }2{{s}^{2}}2{{p}^{6}},\text{ }3{{s}^{2}}3{{p}^{6}}3{{d}^{3}}\] (coloured) \[Z{{n}^{2+}}=\text{ }1{{s}^{2}},\text{ }2{{s}^{2}},\text{ }2{{p}^{6}},\text{ }3{{s}^{2}}3{{p}^{6}}3{{d}^{10}}\] (colourless) \[C{{u}^{+}}=\text{ }1{{s}^{2}},\text{ }2{{s}^{2}},\text{ }2{{p}^{6}},\text{ }3{{s}^{2}},\text{ }3{{p}^{6}}3{{d}^{10}}\] (colourless) \[T{{i}^{4+}}\,=1{{s}^{2}},\,2{{s}^{2}}2{{p}^{6}},\,3{{s}^{2}}\,3{{p}^{6}}\] (colourless) (Colour is produced due to presence of unpaired electron.)
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