A) \[{{10}^{-17}}\,J\]
B) 1 J
C) \[7\times {{10}^{-6}}\,J\]
D) \[{{10}^{-24}}\,J\]
Correct Answer: D
Solution :
The energy of emitted photon \[E=\frac{hc}{\lambda }\] Given: \[\lambda =21\,cm=0.21\,cm\] \[\therefore E=\frac{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}{0.21}={{10}^{-24}}\,J\]You need to login to perform this action.
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