A) 0.8
B) 0.6
C) 0.4
D) 0.2
Correct Answer: B
Solution :
According to Raoult?s law. The relative lowering of vapour pressure is equal to the mole fraction of solute i.e., \[\frac{p-{{p}_{s}}}{p}=\frac{n}{n+N}\] \[or\frac{\Delta p}{p}=\frac{n}{n+N}\] \[\frac{10}{p}=0.2\,\,\therefore \,\,\,p=50\,\operatorname{m}m\] For other solution of same solvent \[\frac{20}{p}=\frac{n}{n+N}\] \[or\frac{20}{50}=\frac{n}{n+N}\] \[0.4=\frac{n}{n+N}\] (mole fraction of solute) So, mole fraction of solvent = 1 ? 0.4 = 0.6You need to login to perform this action.
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