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NEET AIPMT SOLVED PAPER 1998

  • question_answer
                                      Two particles A and B are connected by a rigid rod AB. The rod slides along perpendicular rails as shown here. The velocity of A to the right is 10 m/s. What is the velocity of B when angle \[\alpha ={{60}^{o}}\]?                                                                                                                                                                

    A)                            9.8 m/s     

    B)                 10 m/s

    C)                 5.8 m/s                

    D)                 17.3 m/s

    Correct Answer: D

    Solution :

                    Let the velocity along x and y axes be \[{{v}_{x}}\] and \[{{v}_{y}}\] respectively.                 \[\therefore {{v}_{x}}=\frac{dx}{dt}and\,{{v}_{y}}=\frac{dy}{dy}\]                 From figure,                 \[\tan \alpha =\frac{y}{x}\]                 \[\Rightarrow y=x\tan \alpha \]                 Differentiating Eq. (i) w.r.t. \[t\], we get                 \[\frac{dy}{dt}=\frac{dx}{dt}\tan \alpha \]                 \[\Rightarrow \]               \[{{v}_{y}}={{v}_{x}}\tan \alpha \]                 Here,  \[{{v}_{x}}=10\,m/s\,,\,\alpha ={{60}^{o}}\]                 \[\therefore {{v}_{y}}=10\,\tan {{60}^{o}}=10\sqrt{3}=17.3\,m/s\]


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