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NEET AIPMT SOLVED PAPER 1998

  • question_answer
                    If nearly \[{{10}^{5}}C\] liberate 1 g equivalent of aluminium, then the amount of aluminium (equivalent weight 9) deposited through electrolysis in 20 min by a current of 50 amp will be:            

    A)                 0.6 g                      

    B)                 0.09 g

    C)                                            5.4 g  

    D)                 10.8 g

    Correct Answer: C

    Solution :

                    Total charge flowing through electrolyte                 Q = it                 \[=50\times 20\times 60\]                 \[=6\times {{10}^{4}}\,C\]                 105 C release = 9 g of Al                 \[\therefore 6\times {{10}^{4}}\,C\,\]would release                 \[=\frac{9\times 6\times {{10}^{4}}}{{{10}^{5}}}g\]                 \[=5.4\,g\,of\,Al\]


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