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NEET AIPMT SOLVED PAPER 1998

  • question_answer
                    Light of wavelength \[5000\overset{\text{o}}{\mathop{\text{A}}}\,\] falls on a sensitive plate with photoelectric work function of 1.9 eV. The kinetic energy of the photoelectron emitted will be:                                                                                

    A)                 0.58 eV

    B)                 2.48 eV                                

    C)                 1.24 eV                

    D)                 1.16 eV                  

    Correct Answer: A

    Solution :

                                              Energy of photon is given by                 \[E=\frac{hc}{\lambda }=\frac{12375}{\lambda \,({\AA})}eV\]                 \[\therefore E=\frac{12375}{5000}=2.48\,eV\]                 Einstein?s photoelectric equation is                 \[{{E}_{k}}=E-W\]                 \[=2.48\,eV-1.9\,eV\]                 \[=0.58\,eV\]


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