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NEET AIPMT SOLVED PAPER 1998

  • question_answer
                    The transfer ratio \[\beta \] of a transistor is 50. The input resistance of the transistor when used in the common emitter configuration is \[1\,k\,\Omega \]. The peak value of the collector AC current for an AC input voltage of 0.01 V peak is:                                                                                                                             

    A)                 \[100\,\mu A\]                 

    B)                 \[0.01\,mA\]                     

    C)                 \[0.25\,mA\]                     

    D)                 \[500\,\mu A\]

    Correct Answer: D

    Solution :

                    Key Idea: In common emitter configuration of a transistor, the input current is a base current.. Input current                 \[{{i}_{B}}=\frac{\Delta \,{{V}_{B}}}{{{R}_{B}}}\]                 \[=\frac{0.01}{1000}={{10}^{-5}}\,A\]                 Also current gain                 \[\beta =\frac{{{i}_{C}}}{{{i}_{B}}}\] \[\therefore {{i}_{C}}=\beta {{i}_{B}}=50\times {{10}^{-5}}\,A\]                 \[=500\times {{10}^{-6}}\,A=500\,\mu A\]


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