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NEET AIPMT SOLVED PAPER 1998

  • question_answer
                    Number of neutrons in a parent nucleus X, which gives \[_{7}{{N}^{14}}\] nucleus after two successive \[\beta \]-emmissions would be:                                                                                                                                            

    A)                 9 

    B)                 6

    C)                 7            

    D)                                            8             

    Correct Answer: B

    Solution :

                    After emitting a \[\beta \] particle, atomic number is increased by one unit and atomic weight has no change. So the atomic number of parent nucleus will be 5.                 \[_{5}{{X}^{14}}\xrightarrow[{}]{-\beta }{{\,}_{6}}{{Y}^{14}}\xrightarrow[{}]{-\beta }{{\,}_{7}}{{N}^{14}}\]                                Number of neutrons = Mass number ? Number of proton                 = 14 - 5 = 9


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