A) 5
B) 2
C) 4
D) 6
Correct Answer: D
Solution :
Total no. of electrons in \[O_{2}^{2-}\] = 16 + 2 = 18 According to MOT, the configuration of \[O_{2}^{2-}\] is \[\sigma \,1{{s}^{2}},\,\sigma \,*\,1{{s}^{2}},\,\sigma 2{{s}^{2}},\,\sigma *\,2{{s}^{2}},\sigma \,2p_{x}^{2},\,\pi 2p_{y}^{2}\] \[\pi \,2p_{z}^{2},\,\pi *\,\,2p_{y}^{1}\,\pi *\,\,2p_{z}^{1}\] Orbitals with represent and bonding M.O. so, the number of anti bonding electrons = 6
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