NEET AIPMT SOLVED PAPER 1998

  • question_answer
                    The second order Bragg diffraction of X-rays with \[\lambda =1.0\,\overset{\text{o}}{\mathop{\text{A}}}\,\] from a set of parallel planes in a metal occurs at an angle 60°. The distance between the scattering planes in the crystals is:                   

    A)                 \[0.575\,\overset{\text{o}}{\mathop{\text{A}}}\,\]

    B)                      \[1.00\,\overset{\text{o}}{\mathop{\text{A}}}\,\]

    C)                 \[2.00\,\overset{\text{o}}{\mathop{\text{A}}}\,\]

    D)                 \[1.17\,\overset{\text{o}}{\mathop{\text{A}}}\,\]

    Correct Answer: D

    Solution :

                    According to Bragg?s equation                  \[n=2\,\lambda =1\,\theta ={{60}^{o}}\,d=?\]                 \[2\times 1=2\times d\times \sin {{60}^{o}}\]                 \[2\times 1=2\times d\times \frac{\sqrt{3}}{2}\]                 \[d=\frac{2}{\sqrt{3}}=\frac{2}{1.7}=1.17\,{\AA}\]


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