A) 1.0 mole of \[{{H}_{2}}O\] is produced
B) 1.0 mole of NO will be produced
C) all the oxygen will be consumed
D) all the ammonia will be consumed
Correct Answer: C
Solution :
\[4N{{H}_{3}}(g)+5{{O}_{2}}(g)\xrightarrow[{}]{{}}4NO(g)+6{{H}_{2}}O(\ell )\] \[4\,mol\,+5\,mol\,\xrightarrow[{}]{{}}4\,mol+\,6\,mol\] According to equation 1 mole of \[{{O}_{2}}\] requires = 4/5 = 0.8 mole of \[N{{H}_{3}}\] While 1 mole of \[N{{H}_{3}}\] requires \[=\frac{5}{4}=1.25\,mole\,of\,{{O}_{2}}\] As there is 1 mole of \[N{{H}_{3}}\] and 1 mole of \[{{O}_{2}}\]. So, all oxygen will be consumed.You need to login to perform this action.
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