A) \[\ln \,({{C}_{1}})\]
B) \[\ln \,({{C}_{2}}/{{C}_{1}})\]
C) \[\ln \,({{C}_{2}})\]
D) \[\ln \,({{C}_{1}}+{{C}_{2}})\]
Correct Answer: B
Solution :
\[\Delta G=-n{{E}^{o}}\,F\] For concentration cell \[E=\frac{RT}{nF}\ln \,\frac{{{C}_{2}}}{{{C}_{1}}}\] In it R, T, n and F are constant. So E is based upon- In \[{{C}_{2}}/{{C}_{1}}\] \[\Delta G=-nEF\] \[=-nF\times \frac{RT}{nF}\ln \frac{{{C}_{2}}}{{{C}_{1}}}=-RT\,\ln \,\frac{{{C}_{2}}}{{{C}_{1}}}\] So, at constant temperature \[\Delta G\] depends upon In \[\ln \,{{C}_{2}}/{{C}_{1}}\]You need to login to perform this action.
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