with \[RMgX\] leads to formation of:
A) RCHOHR
B) \[RCHOHC{{H}_{3}}\]
C) \[RC{{H}_{2}}C{{H}_{2}}OH\]
D)
Correct Answer: C
Solution :
\[R-C{{H}_{2}}-C{{H}_{2}}-O-MgX\] \[R-C{{H}_{2}}-C{{H}_{2}}-OH\xleftarrow{{{H}_{2}}O/{{H}^{+}}}\] \[+Mg(OH)\,X\]
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