• question_answer
                    The first ionization potential (in eV) of Be and B, respectively are:                                            

    A)                 8.29, 9.32            

    B)                 9.32, 9.32                            

    C)                 8.29, 8.29                            

    D)                 9.32, 8.29

    Correct Answer: D

    Solution :

                    First ionisation potential of Be (completely filled orbital) is greater than boron due to stable configuration                         \[_{4}Be=1{{s}^{2}},\,\,2{{s}^{2}}\]                         \[_{5}B=1{{s}^{2}},\,\,2{{s}^{2}}2{{p}^{1}}\]                 Order of attraction of electrons towards nucleus 2s > 2p, so more amount of energy is required to remove the electron with 2s-orbital in comparison to 2porbital. So ionisation potential of Be is 9.32 eV and B is 8.29 eV.

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