A) 50% colourblind sons and 50% carrier daughters
B) colourblind sons and carrier daughters
C) normal males and carrier daughters
D) colourblind sons and 50% carrier daughters
Correct Answer: B
Solution :
Colourblindness is sex-linked recessive character carried by X chromosome. Since males have only one X chromosome (XY), presence of gene for colour blindness on X chromosome (X) would cause colour blindness while in woman both chromosomes should have the gene for colour blindness to appear. \[{{X}^{C}}X\] woman would be carriers for the disease. A cross between XY (normal man) and colour blind woman \[({{X}^{C}}{{X}^{C}})\] would produce all colour blind son and carrier daughter. Result of this cross is: 1. Colourblind sons. 2. Carrier daughters.You need to login to perform this action.
You will be redirected in
3 sec