A) 16.758 MeV
B) 1.6758 MeV
C) 0.16758 MeV
D) 0.016758 MeV
Correct Answer: C
Solution :
\[\underset{(Mass=34.96903\,amu)}{\mathop{_{16}{{S}^{35}}}}\,\xrightarrow[{}]{-\beta }\,\,\underset{(Mass=34.96885)}{\mathop{_{17}{{C}^{35}}}}\,\] Mass defect = (34.96903 ? 34.96885) amu = 0.00018 amu Energy = 0.00018 \[\times \] 931 MeV = 0.16758 MeVYou need to login to perform this action.
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