A) \[2\times {{10}^{2}}\] year
B) \[3\times {{10}^{3}}\] year
C) \[3.3\times {{10}^{4}}\] year
D) \[4\times {{10}^{3}}\] year
Correct Answer: B
Solution :
Radioactive decay is first order reaction. So, \[\lambda =\frac{0.693}{{{T}_{1/2}}}\] \[\therefore {{T}_{1/2}}=\frac{0.693}{2.31\times {{10}^{-4}}}\,year\] \[=0.3\times {{10}^{4}}=3\times {{10}^{3}}\,year\]You need to login to perform this action.
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