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NEET AIPMT SOLVED PAPER 1999

  • question_answer
                    A potentiometer consists of a wire of length 4m and resistance \[10\,\,\Omega \]. It is connected to a cell of emf 2V. The potential gradient of wire is:                                                                                                                            

    A)                 0.5 V/m  

    B)                 2 V/m   

    C)                 5 V/m 

    D)                 10 V/m

    Correct Answer: A

    Solution :

                    Potential gradient \[=\frac{Potential\,applied}{Length\,of\,wire}\]                 \[\therefore \]  \[k=\frac{V}{L}\]                 Given, V = 2 V, L = 4m                 \[\therefore k=\frac{2}{4}=0.5\,V/m\]


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