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NEET AIPMT SOLVED PAPER 1999

  • question_answer
                    A 500 kg car takes a round turn of radius 50 m with a velocity of 36 km/h. The centripetal force is:

    A)                                                                                                                                                            250 N

    B)                 750 N                    

    C)                 1000 N    

    D)                 1200 N

    Correct Answer: C

    Solution :

                             The centripetal force required for a car (mass m) to take a sharp turn of radius r with velocity v is                 \[F=\frac{m{{v}^{2}}}{r}\]                 Given, m = 500 kg,                 v = 36 km/h = \[36\times \frac{5}{18}=10\,m/s\,,\,r=50\,m\]                 Hence,      \[F=\frac{500\times {{(10)}^{2}}}{50}=1000\,N\]


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