A) \[6.63\times {{10}^{-33}}\,m\]
B) \[6.63\times {{10}^{-34}}\,m\]
C) \[6.63\times {{10}^{-35}}\,m\]
D) \[6.65\times {{10}^{-36}}\,m\]
Correct Answer: A
Solution :
\[p=\frac{h}{\lambda }\] (de-Broglie equation) \[\lambda =\frac{h}{mv}(\because \,\,p=mv)\] \[\lambda =\frac{6.63\times {{10}^{-34}}\,kg\,{{m}^{2}}/s}{{{10}^{-3}}\,kg\times 100\,m/s}=6.63\times {{10}^{-33}}\,m\]
You need to login to perform this action.
You will be redirected in
3 sec
