A) \[0.142\,c{{m}^{-1}}\]
B) \[0.66\,c{{m}^{-1}}\]
C) \[0.918\,\,c{{m}^{-1}}\]
D) \[1.12\,c{{m}^{-1}}\]
Correct Answer: B
Solution :
\[{{K}_{s}}\] (sp. conductivity) \[=\frac{1}{R}\times \frac{l}{a}\] \[\frac{l}{a}=\] cell constant of cell So, 0.012 \[oh{{m}^{-1}}\,c{{m}^{-1}}=\frac{1}{55\,ohm}\times \frac{l}{a}\] \[\frac{l}{a}\] (cell constant) \[=55\times 0.012=0.66\,c{{m}^{-1}}\]
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