A) 0.5 V
B) 1.9 V
C) 1.95 V
D) 2 V
Correct Answer: C
Solution :
Key Idea: Terminal voltage across the cell decreases due to voltage drop across internal resistance. The current flowing in the circuit is \[i=\frac{E}{R+r}\] Given, E = 2 V, R = 3.9 \[\Omega \], r = 0.1 \[\Omega \] \[So,i=\frac{2}{3.9+0.1}=\frac{2}{4.0}=0.5\,A\] The voltage drop across internal resistance, \[V'=ir=0.5\times 0.1\] 1 = 0.05 V Thus, terminal voltage across cell is, \[V=E-ir=E-V'\] \[=2-0.05=1.95\,V\]You need to login to perform this action.
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