A) ether
B) ketone
C) acetic acid
D) acetaldehyde
Correct Answer: D
Solution :
\[CH\equiv \equiv CH+{{H}_{2}}O\xrightarrow{H{{g}^{2+}}/{{H}^{+}}}\underset{\begin{smallmatrix} \text{Keto form (stable)} \\ \text{tautomerism takes place} \end{smallmatrix}}{\mathop{C{{H}_{3}}-CHO}}\,\] \[\underset{\begin{smallmatrix} | \\ H \end{smallmatrix}}{\mathop{C}}\,H=\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{C}}\,H\leftarrow \to C{{H}_{3}}-\underset{\begin{smallmatrix} || \\ O \end{smallmatrix}}{\mathop{C}}\,-H\]
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