A) \[12\times {{10}^{-2}}\]
B) \[14\times {{10}^{-4}}\]
C) \[22\times {{10}^{-11}}\]
D) \[32\times {{10}^{-12}}\]
Correct Answer: D
Solution :
\[\underset{2\times {{10}^{-4}}\,M}{\mathop{Ca{{F}_{2}}}}\,\underset{2\times {{10}^{-4}}\,M}{\mathop{C{{a}^{2+}}}}\,+\underset{2\times 2\times {{10}^{-4}}\,M}{\mathop{C{{F}^{-}}}}\,\] \[{{K}_{sp}}\] of \[Ca{{F}_{2}}=[C{{a}^{2+}}]{{[{{F}^{-}}]}^{2}}\] \[=[2\times {{10}^{-4}}]{{[4\times {{10}^{-4}}]}^{2}}\] \[=32\times {{10}^{-12}}\,{{(mol/L)}^{2}}\]
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