A) 1.01
B) 10
C) 10.1
D) 100
Correct Answer: D
Solution :
w = 0.15 g, W = 15 g, \[\Delta {{T}_{b}}={{0.216}^{o}}C,\] \[{{K}_{b}}=2.16,\,\,m=?\] \[m=\frac{1000\times {{K}_{b}}}{\Delta {{T}_{b}}}=\frac{w}{W}\] \[=\frac{1000\times 2.16\times 0.15}{0.216\times 15}=100\]You need to login to perform this action.
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