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NEET AIPMT SOLVED PAPER 2000

  • question_answer
                    ABC is a right angled triangular plate of uniform thickness. The sides are such that AB > BC as shown in figure. \[{{I}_{1}},\,{{I}_{2}},\,{{I}_{3}}\] are moments of inertia about AB, BC and AC respectively. Then which of the following relations is correct?                                                                                                                                            

    A)                 \[{{I}_{1}}={{I}_{2}}={{I}_{3}}\] 

    B)                 \[{{I}_{2}}>{{I}_{1}}>{{I}_{3}}\] 

    C)                 \[{{I}_{3}}<{{I}_{2}}<{{I}_{1}}\] 

    D)                 \[{{I}_{3}}>{{I}_{1}}>{{I}_{2}}\]

    Correct Answer: B

    Solution :

                    The moment of inertia of a body about an axis depends not only on the mass of the body, but also on the distribution of mass about the axis. For a given body mass is same, so it will depend only on the distribution of mass about the axis.                 The mass is farthest from axis BC, so \[{{l}_{2}}\] is maximum. Mass is nearest to axis AC, so \[{{l}_{3}}\] is minimum.                 Hence, the correct sequence will be                 \[{{I}_{2}}>{{I}_{1}}>{{I}_{3}}\]                 Note:    In a rotational motion, moment of inertia is also known as rotational inertia.


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