A) 4.68 g
B) 2.34 g
C) 1.17 g
D) 9.36 g
Correct Answer: A
Solution :
Given Half-life \[({{t}_{1/2}})=3\,h\] Initial mass \[({{N}_{0}})=300g\] Total time (T) = 18 h Mass left (N) = ? We know that, \[\frac{N}{{{N}_{0}}}={{\left( \frac{1}{2} \right)}^{n}}\] where n = number of half life \[n=\frac{Total\,time}{Half-life}=\frac{18}{3}=6\] So, \[\frac{N}{300}={{\left( \frac{1}{2} \right)}^{6}}\] \[or\frac{N}{300}=\frac{1}{64}\] \[N=\frac{300}{64}=4.68\,g\]You need to login to perform this action.
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