A) -357 kJ
B) -731 kJ
C) -773 kJ
D) -229 kJ
Correct Answer: B
Solution :
\[\Delta G\] of formation of different substances are as \[2\,S{{O}_{2}}\,=-544\,kJ\] \[2ZnS=-293\,kJ\] \[2ZnO=-480\,kJ\] For the reaction \[2ZnS+3{{O}_{2}}(g)\xrightarrow[{}]{{}}2ZnO(s)+2S{{O}_{2}}(g)\] \[\Delta G=[\Delta {{G}_{(products)}}-\Delta {{G}_{(reac\tan ts)}}]\] \[=[(-480)+(-544)-(-293)]\] \[=-1024+293\] = - 731 kJYou need to login to perform this action.
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