A) 7 cm
B) 7.5 cm
C) 10.5 cm
D) \[\frac{14}{3}\]cm
Correct Answer: C
Solution :
Refractive index \[(\mu )=\frac{\operatorname{Re}al\,depth}{Apparent\,depth}\] Refractive index (\[\mu \]) = 1.5 Apparent depth = 2 + 5=7 cm \[So,1.5=\frac{\operatorname{Re}al\,depth}{7}\] \[\therefore \operatorname{Re}al\,depth=1.5\times 7=10.5\]You need to login to perform this action.
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