A) \[C{{H}_{3}}-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-O-O-H\]
B) \[{{H}_{3}}B{{O}_{3}}\]
C) \[{{B}_{2}}{{H}_{6}}/NaOH-{{H}_{2}}{{O}_{2}}\]
D) \[{{H}_{2}}{{O}_{4}}/{{H}_{2}}O\]
Correct Answer: C
Solution :
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