A) 25 W bulb
B) 100 W bulb
C) Both bulbs will have equal resistance
D) Resistance of bulbs cannot be compared
Correct Answer: A
Solution :
Power of electric bulb \[P=\frac{{{V}^{2}}}{2R}\] So, resistance of electric bulb \[R=\frac{{{V}^{2}}}{P}\] Given, \[{{P}_{1}}=25\,W,\,\,{{P}_{2}}=100\,W,\,{{V}_{1}}={{V}_{2}}=220\,V\] Therefore, for same potential difference V, \[R\,\propto \,\,\frac{1}{P}\] Thus, we observe that for minimum power, resistance will be maximum and vice-versa. Hence, resistance of 25 W bulb is maximum and 100 W bulb is minimum.
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