NEET AIPMT SOLVED PAPER 2000

  • question_answer
                    A charge q is placed at the corner of a cube of side \[a\]. The electric flux through the cube is:

    A)                                                                                                                                                                                                         \[\frac{q}{{{\varepsilon }_{0}}}\]                              

    B)                 \[\frac{q}{3{{\varepsilon }_{0}}}\]                           

    C)                 \[\frac{q}{6\,{{\varepsilon }_{0}}}\]                        

    D)                 \[\frac{q}{8\,{{\varepsilon }_{0}}}\]

    Correct Answer: D

    Solution :

                    According to Gauss's law, the electric flux through a closed surface is equal to \[\frac{1}{{{\varepsilon }_{0}}}\]times the net charge enclosed by the surface.                 Since, q is the charge enclosed by the surface, then electric flux \[\phi =\frac{q}{{{\varepsilon }_{0}}}\]                 If charge q is placed at a corner of cube, it will be divided into 8 such cubes. Therefore, electric flux through the cube is                 \[\phi '=\frac{1}{8}\left( \frac{q}{{{\varepsilon }_{0}}} \right)\]


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