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NEET AIPMT SOLVED PAPER 2000

  • question_answer
                    If \[\Delta E\] is the heat of reaction for \[{{C}_{2}}{{H}_{5}}OH(l)+3{{O}_{2}}(g)\xrightarrow{{}}2C{{O}_{2}}(g)+3{{H}_{2}}O(l)\] at constant volume, the \[\Delta H\] (heat of reaction at constant pressure) at constant temperature is:

    A)                                                         \[\Delta H=\Delta E+RT\]             

    B)                 \[\Delta H=\Delta E-RT\]

    C)                 \[\Delta H=\Delta E-2RT\]

    D)                 \[\Delta H=\Delta E+2RT\]

    Correct Answer: B

    Solution :

                    We know that                 \[\Delta H=\Delta E+\Delta nRT\]                 where \[\Delta n\] = number of moles of gaseous product                 - number of moles  of gaseous reactant                 = 2 - 3 = - 1                 So,    \[\Delta H=\Delta E-RT\]


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